I don't think you have specified the question too well. That list of 16 isn't a sensible list of outcomes with regard to the experiment you're interested in. But before I get into this more Quote:
The Probability of two consecutive Heads in 4 coin tosses is derived from the formula (Gardner, Berlkamp below)
1(F(n+2)/(2^n))
where F(n+2) is the (n+2)th Fibonacci number
In our example the value is 0.1875 (3/16).
For the last question asked, the probability of two consecutive Heads OR 2 consecutive Tails the result is a Probabilistic OR which yields 0.375 (6/16).

What exactly are you saying here? Your formula above has an 'n'. If you take the 'n' to be the coin tosses (you didn't define 'n') then you would not have the answer you gave, right?
Last edited by Calinor; Apr 6, 2009 at 2:56pm.
